Answer by Copperfield for Which is the fastest way to compare two float value...
you need to set a tolerance range, such that if the difference between a and b is bellow they are considered equals>>> def is_close(a, b, tol=1e-9): return abs(a-b) <= tol>>>...
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I have two float value ("a" and "b") in Python 3 and each float value can have from 5 to 15 decimal point. The problem is that when two value are equal for me, python return me a False....
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